Given the function f(x)=x^2+10x+23f(x)=x 2
+10x+23, determine the average rate of change of the function over the interval -9 \ le x \ le 0−9≤x≤0.

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

provide more details to solve it

step-by-step explanation: