For 4 weeks in June, Cameron biked 3 1/4 miles each week and swam 2 1/2 miles each week. For 3 weeks in July, he biked 4 3/4 miles each week and swam 3 1/2 miles each week. How much greater was the total distance Cameron biked and swam in July compared to the total distance he biked and swam in June?

He swam 1/2 mile more and biked 1  1/4 mile more in July

Step-by-step explanation:

June -- Bike    4 * ( 3  1/4)  = 13 miles

            Swim 4 * (2  1/2) = 10 miles

July -- Bike   3 * (4  3/4) = 14 1/4 miles

         Swim   3 * (3  1/2) = 10 1/2 miles

14  1/4 - 13 =   1  1/4

10  1/2 - 10 =  1/2

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft