The probability that a male professional golfer makes a hole-in-one is 1/2780. Suppose 36 professional male golfers play the sixth hole during a round of golf. Let the random variable X be the number of golfers in the group of 36 who make a hole-in-one. Calculate the probability that exactly four of the 36 golfers make a hole-in-one on the sixth hole – as actually happened during the 1989 U. S. Open

The right solution  is "".

Step-by-step explanation:

According to the question,

The probability that male professional golfer makes hole in one will be:

Number of players,

n = 36

and,

By using the Binomial theorem, we get

⇒

Bu substituting the values, we get

or,

my acc plz

step-by-step explanation:

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation: