(x+5)(x+4)(x-2)-(x^2+11x-9)(x+1)+5x ^2 Can someone help me to prove that the value of the following expression does not depend on the value of variable x

(x+5)•(x+4)•(x-2)•(x2+11x-9)•(x+26)

STEP

2

:

Equation at the end of step 2

(((x+5)•(x+4)•(x-2))•(x2+11x-9))•(x+26)

STEP

3

:

Equation at the end of step 3

((x+5)•(x+4)•(x-2)•(x2+11x-9))•(x+26)

STEP

4

:

Trying to factor by splitting the middle term

4.1 Factoring x2+11x-9

The first term is, x2 its coefficient is 1 .

The middle term is, +11x its coefficient is 11 .

The last term, "the constant", is -9

Step-1 : Multiply the coefficient of the first term by the constant 1 • -9 = -9

Step-2 : Find two factors of -9 whose sum equals the coefficient of the middle term, which is 11 .

-9 + 1 = -8

-3 + 3 = 0

-1 + 9 = 8

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

4

:

(x+5)•(x+4)•(x-2)•(x2+11x-9)•(x+26)

Step-by-step explanation:

company a

step-by-step explanation:

using the linear regression models , it is found that company a   pays about $14 more. but using the same regression (linear) company b pays about $10 more.

so company a pays more than b

i don't see any

step-by-step explanation: