If ∠3 = 46°, then ∠6 =
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Jane evaluates x^2-3x+5 for x=2 below. step 1: (-2)^2-()+5 step 2: =-4+6+5 step 3: =7 what, if any, was jane’s mistake? a)jane made no mistakes. b)jane incorrectly evaluated(-2)^2 in step 2. c)jane incorrectly added the terms in step 3. d)jane incorrectly substituted in x=-2in step 1.
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