Given: line BC is parallel to line ED
m∠ABC = 70°
m∠CED = 30°

Prove: m∠BEC = 40°

True, mBEC=40º

Step-by-step explanation:

Given that , we know that ABC = BED = 70º because of corresponding angle theorem.

Furthermore,

BED = BEC + CED

Given that CED = 30º, we can find BEC.

70º=30º + BEC

BEC = 40º

I hope this helps! Let me know if you have any questions :)

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.