The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 36 liters, and standard deviation of 7 liters. A) What is the probability that daily production is less than 23.4 liters? Use technology (not tables) to get your probability.

Answer=
(Round your answer to 4 decimal places.)

B) What is the probability that daily production is more than 45.7 liters? Use technology (not tables) to get your probability.

Answer=
(Round your answer to 4 decimal places.)

A) 0.0359

B) 0.0829

Step-by-step explanation:

A) Using normalcdf on your calculator, or using something online, you can plug (-1000, 23.4, 36, 7) to represent the lower bound, upper bound, mean, and standard deviation respectively. The probability that daily production is less than 23.4 liters is 0.0359

B) Similarly, we can plug (45.7, 1000, 36, 7) in as the upper bound is infinity, and the lower bound if 45.7. Our answer is then 0.0829

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

ur mom

step-by-step explanation: