Sea grass grows on a lake. The rate of growth of the grass is / = , where is a constant. a. Find an expression for , the amount of grass in the lake (in tons), in terms of , the number of years, if the amount of grass is 100 tons initially, and 120 tons after one year.
b. In how many years will the amount of grass available be 300 tons?
c. If fish are now introduced into the lake and consume a consistent 80 tons/year of sea grass, how long will it take for the lake to be completely free of sea grass?

Step-by-step explanation:

Given

--- initial

--- after 1 year

Solving (a): The expression for g

Since the rate is constant, the distribution of G follows:

implies that:

Substitute

Divide both sides by 100

Take natural logarithm of both sides

So, the expression for G is:

Solving (b): t when G(t) = 300

We have:

Divide both sides by 100

Take natural logarithm

Solve for t

--- approximated

Solving (c): When there will be no grass

Reduction at a rate of 80 tons per year implies that:

To solve for t, we set G(t) = 0

Rewrite as

Divide both sides by 100

Take natural logarithm of both sides

Plot the graph of:

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

(a) the volume of the cone is 20/3 in3

hence, option a is correct.