Given the equation −4square root of x minus 3 = -12, solve for x and identify if it is an extraneous solution. A. x = 0, solution is extraneous
B. x = 0, solution is not extraneous
C. x = 12, solution is extraneous
D. x = 12, solution is not extraneous

D.    x = 12, solution is not extraneous

Step-by-step explanation:

-4√(x - 3) = -12

Divide both sides by -4

√(x - 3) = 3

Square both sides

x - 3 = 9

add 3 to both sides

x = 12

To see if it's extraneous plug into original problem

-4√(12 - 3) = -12

-4√(9) = -12

-4 * 3 = -12

-12 = -12

not extraneous

y/x=18

step-by-step explanation: