Jose spends a winter day recording the temperature once every three hours for science class. At 9 am, the temperature was -2.5°F. Between 9am and noon, the temperature rose 17.9°F. Between noon and 3pm, the temperature decreased by 17.7°F. Between 3pm and 6pm, the temperature decreased by 14.8°F. What was the temperature at 6pm?

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

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step-by-step explanation:

step-by-step explanation:

2+2 obliviously is 4.