2x + z = 46
3z= 18
2y + z= 40

x=20, y=17, and z=6 or (20,17,6)

Step-by-step explanation:

Hi there!

We're given the system of equations:

2x+z=46

3z=18

2y+z=40

and we need to solve for x, y, and z

first, let's find the value of z, as we have z by itself (no other variables) in 3z=18

divide both sides by z

z=6

the value of z is found :)

now we can use z=6 to find the value of the other variables; for example, plug z as 6 into 2x+z=46 to solve for x

2x+6=46

subtract 6 from both sides

2x=40

divide by 2

x=20

Finally, let's find y

once again, we can substitute z as 6 in the equation 2y+z=40 to find y

2y+6=40

subtract 6 from both sides

2y=34

divide by 2

y=17

so the answer is: x=20, y=17, and z=6; if you need it in a point it's (20,17,6)

Hope this helps! :)

answer: sorry

step-by-step explanation: can you tell me pls how to find the rational of two integers

found it xd it ok yt