What is the total number of digits required in numbering the pages of a book, which has 1, 150 pages?

3,493 digits

Step-by-step explanation:

Total pages of the book = 1,150

Page 1 - 9 = 9 digits

Page 10 - 99

= 2 * 90 pages

= 180 digits

Page 100 - 999

= 3 × 900 pages

= 2,700 digits

Page 1000 - 1,150

= 4 × 151 pages

= 604 digits

Total digits required in numbering 1,150 pages = 9 + 180 + 2,700 + 604

= 3,493 digits

Total digits required in numbering 1,150 pages = 3,493 digits

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value