El perímetro de un rectángulo es 58 y su base excede en 10 a su ancho, ¿Cuánto mide la base? AYUD

The base is 19.5.

Step-by-step explanation:

The given question is, "The perimeter of a rectangle is 58 and its base exceeds its width by 10, how long is the base?"

Perimeter = 58

Base, l = 10+b

The perimeter of a rectangle is :

P = 2(l+b)

58 = 2(10+b+b)

29 = (10+2b)

29-10 = 2b

19 = 2b

b = 9.5

Base, l = 10 + 9.5

= 19.5

Hence, the base is 19.5.

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72