An arrow is shot vertically upward from a platform 19ft high at a rate of 163ft/sec. When will the arrow hit the ground? Use the formula: h=−16t2+v0t+h0. (Round your answer to the nearest tenth.)

10.3 s

Step-by-step explanation:

Given

The height of the arrow is given by

At  and

When arrow hits ground, h becomes 0 i.e.

Neglecting the negative value of t

So, the arrow hits the ground after 10.30 s

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are