Which of the following sets of numbers could not represent the three sides of a right triangle?

25, 32, 40 can not form a right angle triangle.

Step-by-step explanation:

By Pythagoras theorem,

⇒ (40)² = (25)² + (32)²

⇒ 1600 = 625 + 1024

⇒ 1600 ≠ 1689

option b

Step-by-step explanation:

according to the pythagoras theorem to be right angled triangle the sum of square of two smaller sides must be equal to the square of hypotenuse.

so ,

20 and 21 are smaller sides and hypotenuse be 29

pythagoras theorem

a^2 + b^2 = c^2

20^2 + 21^2 = 29^2

400 + 441 = 841

841 = 841  (since both sides are equal it forms right angled triangle)

25 and 32 are smaller sides and 40 be hypotenuse

a^2 + b^2 = c^2

25^2 + 32^2 = 40^2

625 + 1024 = 1600

1649 = 1600 (both sides are not equal so it does not form right angle triangle)

30 and 72 are smaller sides whereas 78 is hypotenuse

a^2 + b^2 = c^2

30^2 + 72^2 = 78^2

900 + 5184 = 6084

6084 = 6084 (since both sides are equal it forms right angled triangle )

32 and 60 are smaller sides and 68 is hypotenuse

a^2 + b^2 = c^2

32^2 + 60^2 = 68^2

1024 + 3600 = 4624

4624 = 4624  (since both sides are equal it forms right angled triangle )

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.