2) A block of ice weighs 12 400 kg. It has the shape of a cylinder, with a radius of 1.2 m and a height of 3 m. What is the density of the ice? Give your answer to one decimal place.

= 3.6

Step-by-step explanation:

Do you know how to find the volume of a cylinder? Like any prism, it's area of base x height, in this case the base is a circle of radius 1.2m.

Density is simply mass / volume (kg / m3 ).

clarify its 1.2 x 3 = 3.6

12400 / 3.6 = 3.444 occuring

x+y=90

x=30-y=x

step-by-step explanation:

if you understand you will get the answer

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.