for 1 trial, 3 spinners are spun where each spinner has 3 equal sections labeled 1, 2, and 3. What is the probability that at least two spinners land on 1?

80/121

Step-by-step explanation:

For simplicity,

Probabilities of getting a red, a blue or a green in a single spin are, respectively, 4/11, 4/11 & 3/11.

Therefore, probabilities of getting 2 reds, 2 blues or 2 greens in 2 spins are, 16/121, 16/121 & 9/121 respectively.

Then, total probability of getting same colour both times would be 16/121 + 16/121 + 9/121 = 41/121.

Any other option would result in 2 different colours. Thus, the probability of getting two different colours in 2 spins = 1 - 41/121 = 80/121.