The slope of a line through the points (-2, 4) and (6, b) is - What is the value of b? Explain your method for calculating b.

Work Shown:

m = (y2-y1)/(x2-x1)

m = (b-4)/(6-(-2))

m = (b-4)/(6+2)

m = (b-4)/8

Set this equal to the slope -3/4 and solve for b

(b-4)/8 = -3/4

4*(b-4) = 8*(-3) ... cross multiply

4b-16 = -24

4b = -24+16 ... adding 16 to both sides

4b = -8

b = -8/4

b = -2

Since b = -2, we can replace b with -2

That makes the point (6,b) turn into (6,-2)

Now apply the slope formula to (-2,4) and (6,-2). We should get -3/4 as a result

m = (y2-y1)/(x2-x1)

m = (-2-4)/(6-(-2))

m = (-2-4)/(6+2)

m = -6/8

m = -3/4

So everything works out.

b = -2

Step-by-step explanation:

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.