The height of a ball kicked in the air is modeled by the equation h(t) = -2t^2 +8t +24, where h is the height of the ball in feet and t is the time in seconds. What is the average rate of change of the function over the intervalt t = 2 to t = 5 A. -3

B. -6

C. 3

D. 6

Step-by-step explanation:

The rate of change in any function is the slope of the line between 2 points. Our points are t = 2 and t = 5. But we know that the slope formula also involves the h's for each of those t's. We need to find them first. The slope formula is

, but for us it will look like this (fittted to our needs):

. So we need to find those h's.

when t = 2, plug in a 2 for t and solve for h.

Therefore, and

h(2) = 32 and in coordinate form, (2, 32).

When t = 5, plug in a 5 for t and solve for h.

Therefore, and

h(5) = 14 and in coordinate form, (5, 14). Now we can plug into our slope formula:

, choice B.

The rate of change is -6 which, in words, means that the ball fell 6 feet every 1 second it fell.

the two may have that, even a breakdown is probably offered

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

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