I need help with the following problem please: There are 156 concrete blocks available to make a retaining wall. The bottom three rows will all have the same number blocks. The next six rows will each have two blocks fewer than the road below it. How many blocks are in each row?

Step-by-step explanation:

3x+x-2+x-4+x-6+x-8+x-10+x-12=156

9x-42=156

9x=156+42

9x=198

x=198/9

x=22 is the number of blocks in the first 3 rows.

then you'll have:

20,18,16,14,12 & 10 in each successive row.

proof

3*22+20+18+16+14+12+10=156

66+90=156

156=156

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

22 dimes and 9 nickels

step-by-step explanation: