Jeanne goes to the city park every 7 days for walk. Susan goes to the park every 10 days. If they both went to the park today and met each other, after how many days again will they be in the park and meet again?

70 days

Step-by-step explanation:

We solve using Lowest Common Denominator method

Find and list multiples of each number of days for a walk until the first common multiple is found. This is the lowest common multiple.

Jeanne goes to the city park every 7 days for walk. Susan goes to the park every 10 days.

Hence:

Multiples of 7:

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84

Multiples of 10:

10, 20, 30, 40, 50, 60, 70, 80, 90

Therefore,

LCM(7, 10) = 70

Therefore, the number of days in which they will they be in the park and meet again is 70 days

what is all that apply?

just find the gcf and solve the gcf's until you get each answer i have a really good feeling somethings missing xd (like the dimensions of the fence) *cough *cough *hint *hint

step-by-step explanation: