In ΔGHI, the measure of ∠I=90°, GI = 11, HG = 61, and IH = 60. What ratio represents the sine of ∠G?

60:61

Step-by-step explanation:

From the given triangle

HG = Hypotenuse = 61

GI = Adjacent = 11

IH = Opposite = 60

According to SOH CAH TOA

Sin theta = opposite/hypotenuse

SInce<G = IH/HG

SIn <G = 60/61

The required ratio is 60:61

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2