The perimeter of the rectangle below is 130 units. Find the value of z

9 =z

Step-by-step explanation:

The perimeter of a rectangle is

P = 2(l+w) where l is the length and w is the width

P = 2(3z+2+ 4z)

Combine like terms

P = 2(7z+2)

Substitute in the perimeter

130 = 2( 7z+2)

Divide each side by 2

130/2 = 2/2 ( 7z+2)

65 = 7z+2

Subtract 2 from each side

65-2 = 7z+2-2

63 = 7z

Divide by 7

63/7 = 7z/7

9 =z

ok i think its 32.5

Step-by-step explanation:

3z+2 (which u need to subtract) to get 1z

then 1zx4x=4x

130/4z=32.5

hope i helped

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: