Consider a different experiment: EXPERIMENT: A bag contains 3 red balls, 4 blue balls, 4 green balls and 3 yellow balls. One ball is drawn at random and then returned to the bag. Then a ball is drawn again, possibly the same one or a different one. (a) Specify the sample space (set of outcomes) and probability distribution of the outcomes.
(b) What is the probability that both balls drawn were red balls?
(c) Starting over with all 14 balls back in the bag, what is the probability that both draws were balls of different colors?

a) Sample space = RR, RB, RG, RY, BB, BR, BG, BY, GG, GR, GB, GY, YY, YR, YB, YG .

probability distribution of outcomes

= (3/14*3/14),  (3/14*4/14),  (3/14*4/14),  (3/14*3/14),  (4/14 *4/14 ), (4/14*3/14), (4/14 * 4/14),  (4/14 * 3/14 ),  ( 4/14 *4/14 ),  (4/14*3/14),  ( 4/14 *4/14 ),  

(4/14*3/14),   (3/14 *3/14 ), (3/14*3/14),  (3/14 *4/14 ), ( 3/14 * 4/14 )

b)  0.0459

c) ( 3/14 * 4/14 ) + ( 3/14 * 4/14 ) + ( 3/14 * 3/14 ) + ( 3/14 * 4/14 )

Step-by-step explanation:

Total number of balls = 3 + 4 + 4 + 3 = 14 balls

3 Red balls = 3/14

4 blue balls  = 4/14

4 green balls = 4/14

3 yellow balls = 3/14

a) Determine the sample space and probability distribution of outcomes

since ball is drawn with replacement

Sample space = RR, RB, RG, RY, BB, BR, BG, BY, GG, GR, GB, GY, YY, YR, YB, YG .

i.e. The sample space has 16 possible combination

probability distribution of outcomes

= (3/14*3/14),  (3/14*4/14),  (3/14*4/14),  (3/14*3/14),  (4/14 *4/14 ), (4/14*3/14), (4/14 * 4/14),  (4/14 * 3/14 ),  ( 4/14 *4/14 ),  (4/14*3/14),  ( 4/14 *4/14 ),  

(4/14*3/14),   (3/14 *3/14 ), (3/14*3/14),  (3/14 *4/14 ), ( 3/14 * 4/14 )

b) Determine  P( R and R )

P ( R and R ) = 3/14 * 3/14

                    = 9/196 =  0.0459

C) Determine probability of drawing two different balls

P( R and B ) + P ( R and G ) + P ( R and Y ) + P ( Y and G )

= ( 3/14 * 4/14 ) + ( 3/14 * 4/14 ) + ( 3/14 * 3/14 ) + ( 3/14 * 4/14 )

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation: