In multiplying two real numbers, we are familiar with the so-called “Zero-Product Property” from both Intermediate and College Algebra. Recall that this says that if you have two numbers x and y such that the product xy = 0, then either x = 0, y = 0 or they are both zero. Can the same be said of matrices? In other words, given matrices A and B where AB = 0, does that mean that either A = 0, or B = 0 or both (where 0 denotes the zero matrix here).
Let A= 3 −6
−1 2
Try to construct a 2 × 2 matrix B such that AB is the zero matrix (make sure you clearly show the multiplication). Use two different nonzero columns for B.

marco saved more.   he saved $35 more.

step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

the answer is b.

64

step-by-step explanation:

c=2πr=2·π·8≈64