Use the relative frequency histogram that follows to calculate the proportion of measurements falling into the given interval. Remember that the classes include the left boundary point, but not the right. A relative frequency histogram has a horizontal axis labeled "x" with values from 30.25 to 34.75 and a vertical axis labeled "Relative Frequency" with values from 0.00 to 0.45. The relative frequency histogram has 8 bars of equal width. Each bar is associated with an interval and an approximate value as listed below.
30.50 to 31.00: 0.15
31.00 to 31.50: 0.00
31.50 to 32.00: 0.00
32.00 to 32.50: 0.20
32.50 to 33.00: 0.40
33.00 to 33.50: 0.15
33.50 to 34.00: 0.05
34.00 to 34.50: 0.05
33 or more

0.05

Incorrect: Your answer is incorrect.

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation:

answer: idk wbu

step-by-step explanation: umm..

i'm pretty sure the answer is a. decreases with increase in

the given growth  function for the length of the fish (cm) is

f(m) = 5(1.07)m = 5.35m

where 

m = months

at the end of the study, the length is 9.19 cm. the  time for conducting the study is determined as

5.35m = 9.19

m = 1.7178 months

part a.

the study was performed over a time period  of about 1.72 months. therefore  the domain for  plotting the function is 0 < = m < = 1.72.

note:

if growth  continues at this rate for up to m months, then the domain would be 0< =m< =m.

part b.

the growth function is a linear function.

when m=0, f=0.

therefore the initial growth is zero, which represents the y-intercept.

part c.

assume that the growth function is valid for 0< =m< =9.

the average rate of change of the function is the slope of the linear function, which is 5.35 cm/month.