so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre
so in quadrilateral oabc
< coa + < oab + < ocb + < abc = 360
150 +90+90 + < abc = 360
330 + < abc = 360
< abc = 360 -330 = 30
so < abc = 30
⭐dhruv⭐
Answer from: Quest
c. (3,2,6) is the answer.
Answer from: Quest
or
step-by-step explanation:
we need to solve for 'x' the following equation:
we have that:
⇒
⇒ ⇒
factorizing, we get that:
⇒
then, the solutions are: or
nothing extraneous has been found!
Answer from: Quest
step-by-step explanation:
what is the figure? attach a picture.
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