Consider these loads for a single-family house with 240V systems. Suppose that you’re working in a kitchen that contains one 8 kW counter-mounted cooking unit and two 6 kW wall-mounted ovens. All three appliances are served by the same 240 V branch circuits. This situation is illustrated in the following figure. Load 1: General lighting and receptacle and small appliance loads
Load 2: Cooking equipment loads
Load 3: Special appliance loads
Load 4: Dryer load
Load 5: Heating load Load 6: Largest motor

What would be the demand load for this branch circuit for the loads 1, 2, and 3?

What would be the demand load for this branch circuit for the loads 4, 5, and 6?

This is all the information I have for these questions

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

d

because parallelagram have all 4 angels the same size dependeing and a rectangle and square are oth parallelogram