HELP QUICK, WILL MARK THE BRAINIEST IF I CAN! What is the value of z in the following system of equations?
x + 2y + 3z = 0
2x + y + 3z = 0
3x + 2z =1

x=3 ;y=4.5 ;z=-4

Step-by-step explanation:

x+2y+3z=0

2(x+2y+3z=0)

2x+4y+6z=0 [1]

2x+y+3z=0 [2]

[1] - [2]:(elimination)

(2x+4y+6z)-(2x+y+3z)=0-0

2x+4y+6z-2x-y-3z=0

3y+3z=0 [3] ×2

6y+6z=0

3x+2z=1 [4] ×3

9x+6z=3

([4]×3)-([3]×2): (elimination)

(9x+6z)-(6y+6z)=3-0

9x+6z-6y-6z=3

3x=3

x=3

Substitute x=3 into 3x+2z=1

3(3)+2z=1

9+2z=1

9-1=-2z

8=-2z

z=-4

Substitute z=-4 & x=3 into x+2y+3z=0

3+2y+3(-4)=0

3+2y-12=0

2y-9=0

2y=9

y=4.5

2 apples

step-by-step explanation:

taking away equals subtraction. 6-4=2

the answer would be  

a.

3: 1

step-by-step explanation: