5) The length of a rectangle is 5 more than 10 times the width. The perimeter is 230cm find the length and width of the rectangle. (I need help please!)

length =105 width =10

Step-by-step explanation:

L=10*W+5

P=230

P=2(L+W)

230=2(10W+5+W)

SOLVE FOR W

W=10

L=10*W+5

=10*10+5

L=105

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.