A class' test scores are normally d istributed with a mean of 48 points  and a standard  deviation of 3 points. What percent age of test scores are are between  47 and 52 
points? Round to the nearest hundre dth of a percent.

53.94%

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 48 points

σ is the population standard deviation = 3 points

For x = 47 points

z = 47 - 48/3

= -0.33333

Probability value from Z-Table:

P(x = 47) = 0.36944

For x = 52 points

z = 52 - 48/3

= 1.33333

Probability value from Z-Table:

P(x = 52) = 0.90879

Hence, the probability of test scores that between 47 and 52 points is calculated as:

P(x = 52) - P(x = 47)

= 0.90879 - 0.36944

= 0.53935

Therefore, the percentage of test scores that are between 47 and 52

points is given as:

0.53935 × 100

= 53.935%

Approximately to the nearest hundredth of a percent ≈ 53.94%

you forgot the options, but i found them anyways, the correct answer is "john wilson believes that words and actions based on the intellect are superior to those based on emotions".

john wilson is depicted as an extremely intelligent man. the point of the excerpt is to make a sort of distinction between emotional and rational intelligence. he happens to have both attributes, but he clearly favors his intellectual gifts. at the same time, because of his religious background, he's a little bit conflicted with this and it makes him ashamed.

hope this !

answer:

step-by-step explanation: