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Mathematics, 09.06.2021 21:50 Yamari000

Which equation could be used to find xin AABC?* x = 10/(tan 32'
x = 10 /(sin 32")
x = 10 sin 32
x = 10/(cos 32)
X = 10 cos 32
X = 10 tan 32

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Which equation could be used to find xin AABC?* x = 10/(tan 32'
x = 10 /(sin 32")
x = 1...
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