Find the largest possible rectangular area you can enclose, assuming you have 128 meters of fencing. What is the (geometric) significance of the dimensions of this largest possible enclosure?

Step-by-step explanation:

let the length=x

width=y

P=2(x+y)=128

x+y=128/2=64

y=64-x

area A=xy=x(64-x)=64x-x²

so A or area is maximum if x=32

y=64-32=32

or it is a square of edge=32 meters.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47