What is the x-value of the vertex?

f (x) = (x + 2)^2 - 1

x-value of the vertex:

x-value of the vertex:-2

Solution given:

we have

f(x)=(x+2)²-1

y=x²+4x+3(I)

parameters of parabola are:

a=1

b=4

c=3

we have

vertex=-b/2a=-4/(2*1)=-2

substitute value of x in equation 1.

y=4-8+3= -1

So

vertex(-2,1)

Rewrite the equation in expanded form:

(X+2)^2 -1 = x^2 + 4x + 3

The parabola parameters are : a = 1, b = 4, c = 3

The x vertex is -b/2a = -4/2(1) = -2

Replace x with -2 in the expanded equation to solve for the y vertex:

Y = -1

The vertex is (-2,-1)

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer