3 consecutive integers have a sum of 27. What are the integers?

8,9,10

Step-by-step explanation:

Let x be the first integer

x+1 is the next consecutive integer

x+2 is the third consecutive integer

The sum is 27

x + (x+1) + (x+2) = 27

Combine like terms

3x+3 = 27

Subtract 3 from each side

3x+3-3 =27-3

3x =24

Divide by 3

3x/3 = 24/3

x=8

The integers are

x=8

x+1 =9

X+2 =10

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.