What is h(−8) for h(x)=1/4x^2+7x?

h(-8) = -40

Step-by-step explanation:

Find h(-8) by plugging in -8 as x:

h(x) = 1/4x² + 7x

h(-8) = 1/4(-8)² + 7(-8)

Simplify:

h(-8) = 1/4(64) - 56

h(-8) = 16 - 56

h(-8) = -40

So, the answer is h(-8) = -40

h(-8) = -40

Step-by-step explanation:

all you need to do is substitute x with -8.

1/4x^2+7x

1/4(-8)^2+7(-8)

1/4(64)+(-56)

16-56

-40