The width of a rectangle is 5 meters less than its length. The area is 84 square meters. Find the dimensions of the rectangle

12m x 7m

Step-by-step explanation:

Let us start with the formula fo the area of a rectangle, , where l represents the length of the rectangle and w represents the width of the rectangle.

We are given that the width of a rectangle is 5 meters less than its length. We can set the width as . If the width is , the length must be 5 more than that. We have the length now as .

Now, we can plug in the equation to solve for :

We have two x values. However, we know that length can never be negative. Thus, we know that the width must be 7 meters. The height is 5 more than the width, so we have 12 meters.

The dimensions of the rectangle is 12m x 7m.

I hope this helps! Let me know if you have any questions :)

its 4 because 2 times 2 is 4, if you double the number two you get four

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form