Luke has a set of cards numbered 1 to 8, which he arranges in pairs. He notes the sum of the numbers on each pair of cards and calculates
the lowest common multiple (LCM) of the four sums.

Luke now takes six cards numbered I to 6 but he groups them into
two sets of three. He finds the sums of the numbers in each triple and
then finds the LCM of these two triple sums. What is the smallest
LCM he can obtain?​

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to