Which equation(s) have -4 and 4 as solutions? A. x2 = 8
B. x2 + 16 = 0
C. 2x2 = 32
D. -3x2 = -48
E. 6x2 + 56 = -40
F 27 - 5x2 = -53

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5