Consider the relation y → 4 x−1 for the domain {3, 5, 7, 9} (a) Calculate the values for the range.

{ 11, 19, 27, 35 }

Step-by-step explanation:

To find the range substitute each value of x from the domain into the relation

x = 3 : y → 4(3) - 1 = 12 - 1 = 11

x = 5 : y → 4(5) - 1 = 20 - 1 = 19

x = 7 : y → 4(7) - 1 = 28 - 1 = 27

x = 9 : y → 4(9) - 1 = 36 - 1 = 35

range is { 11, 19, 27, 35 }

19

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.