two lines intersect. One has gradient 4 and y-axis intercept 3. The other has gradient 6 and cuts the y-axis at (0,1). What is the point of interesection of the lines?​

(1, 7 )

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Then the equations of the 2 lines are

y = 4x + 3 → (1)

y = 6x + 1 → (2)

Substitute y = 6x + 1 into (1)

6x + 1 = 4x + 3 ( subtract 4x from both sides )

2x + 1 = 3 ( subtract 1 from both sides )

2x = 2 ( divide both sides by 2 )

x = 1

Substitute x = 1 into either of the 2 equations for corresponding value of y

Substituting into (1)

y = 4(1) + 3 = 4 + 3 = 7

Point of intersection = (1, 7 )

$35.59 in pounds

step-by-step explanation:

if x = 1, then the answer is 3.5