Write standard equation of circle if center is (5,3) and an outside point is (9,6)?

after simplifying it i got: -36.25 as my answer. hope that !

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

i need points

step-by-step explanation:

sorry bubs

i’m sorry but i don’t know sorry