A first number is 4 less than a second number. Four times the first number is 6 more than twice the second. Find the numbers

first number = 7

second number = 11

Step-by-step explanation:

A first number is 4 less than a second number

f = s - 4

Four times the first number is 6 more than twice the second

4f = 2s + 6

Substitute for f = s - 4

4(s - 4) = 2s + 6

distribute

4s - 16 = 2s + 6

subtract 2s from both sides

2s - 16 = 6

add 16 to both sides

2s = 22

Divide both sides by 2

s = 11

Substitute for s = 11 in

f = s - 4

f = 11 - 4

f = 7

7.3

step-by-step explanation: