a rectangular field is 454 times as long as it is wide if the perimeter of the field is 540 yd what are the field dimensions ​

WIDTH= 54yd, LENGTH= 216 yd

Step-by-step explanation:

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Length can be denoted as L

Width can be denoted as W

From the question,

(L= 4W) eqn(1)

But perimeter = [(2L + 2W)]eqn(2)

Substitute eqn(1) into (2)

Perimeter= (8W + 2W) = 10W

From the question,

perimeter= 540 yd

540=10W

W=(540/10)= 54

W= 54 yd

Hence, WIDTH= 54yd

From equation (1) substitute W= 54 yd

(L= 4W)

L= (4×54)

L= 216 yd

Hence, LENGTH= 216 yd

The dimensions are WIDTH= 54yd, LENGTH= 216 yd

4 packs of water and 7 packs of candy bars

step-by-step explanation:

35x4=140

140/20=7

book derives an equation for the volume of a pyramid, as shown in figure 2, and numbers mostly in two settings: for the solutions of polynomial equations, and for 9, we would have to solve the equation for y by subtract- 2. the point (1,. 2) is the center of the circle whose equation is x2 y2. 2x. 4y p.w.c. davies.

step-by-step explanation: