Find the solution set of the inequality \qquad52- 3x < -14.52−3x<−14.52, minus, 3, x, is less than, minus, 14, point \qquad xxx

x > 22

Step-by-step explanation:

Given the inequality;

52- 3x < -14

Subtract 52 from both sides

52 - 3x - 52 < -14 - 52

-3x < -14 - 52

-3x < -66

Divide both sides by -3

-3x/-3 < -66/-3

x > 22

Hence the required inequality is x > 22

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204