What is the area of this figure? Enter enter in the box ___units2

Step-by-step explanation:

U still in school

42 square units

Step-by-step explanation:

We can divide the figure in two triangles and one rectangle

the two triangles are congruent

base  = |-5-2| = 7

height = 2

Total area of the two triangles = (7 *2)/2 * 2 = 14 square units

the rectangle have the length that is equal to the base of the triangles

height = |-2-2| = 4

Area = 7 *4 = 28 square units

Final area = 14+ 28 = 42 square units

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i