As runners in a marathon go by, volunteers hand them small cone shaped cups of water. The cups have the dimensions shown. Abigail sloshes \dfrac23 3 2 ​ start fraction, 2, divided by, 3, end fraction of the water out of her cup before she gets a chance to drink any. What is the volume of water remaining in Abigail's cup?

Volume of water remaining in Abigail's cup = 25.12 cm³

Step-by-step explanation:

As runners in a marathon go by, volunteers hand them small cone shaped cups of water. The cups have the dimensions radius 3 cm and height 8 cm. Abigail sloshes 2/3 of the water out of her cup before she gets a chance to drink any. What is the volume of water remaining in Abigail's cup? Use 3.14 for Pi

Volume of a cone cup = πr²h/3

Radius, r = 3 cm

Height, h = 8 cm

Pi, π = 3.14

Volume of a cone cup = πr²h/3

= (3.14 * 3² * 8) / 3

= (3.14 * 9 * 8) / 3

= 226.08 / 3

= 75.36 cm³

Abigail sloshes 2/3 of the water out of her cup.

What is the volume of water remaining in Abigail's cup

Volume of water Abigail slosh = 2/3 of 75.36 cm³

= 2/3 * 75.36

= 150.72 / 3

= 50.24 cm³

Volume of water remaining in Abigail's cup = Volume of water in the cup - Volume of water Abigail slosh

= 75.36 cm³ - 50.24 cm³

= 25.12 cm³

Volume of water remaining in Abigail's cup = 25.12 cm³

i believe

step-by-step explanation:

from my conclusion c

plz yuo

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