Let △ABC be a right triangle with m∠C = 90°. Given tan ∠A = 0.25, find tan ∠B.

Rule:

If A+B = 90, then tan(A) = 1/( tan(B) ) and tan(B) = 1/( tan(A) )

Since C = 90, this must mean the other two angles A and B are acute and complementary. So A+B = 90 must be the case. This allows us to use that rule above.

So,

tan(B) = 1/( tan(A) )

tan(B) = 1/( 0.25 )

tan(B) = 4

Here's another way to think about it.

If tan(A) = 0.25, then we could have BC = 1 and AC = 4 as the opposite and adjacent sides respectively. That leads to tan(A) = opposite/adjacent = BC/AC = 1/4 = 0.25

When computing tan(B), the BC and AC sides swap roles in terms of opposite and adjacent,

tan(B) = opposite/adjacent = AC/BC = 4/1 = 4.

For any of these cases, we don't involve the hypotenuse AB.

d

step-by-step explanation:

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.