Write one digit on each side of 73 to make a four digit multiple or 36. How many different solutions does this problem have? And what are they.

73 u have to add any digit either at right or left therefore

73+11=

them multiply by 36

73×36

Addison and multiplication is t a e answer

There are two solutions to the problem.

The numbers are 6732 and 2736.

Step-by-step explanation:

36 = 4*9

The four digit number must be divisible by 4 AND by 9.

The last two digits must be divisible by 4.  So only 2 and 6 are possible.

X732, X736.

X must be such that the four-digit number is divisible by 9.

7+3+2=12, so a 6 to make the sum of digits = 18, hence divisible by 9.  So 6732 is divisible by 36.

7+3+6 = 16, so a 2 to make 2736 whose sum of digits = 18, hence the four digit number is divisible by 9.  So 2736 is divisible by 36.

There are two solutions to the problem.

The numbers are 6732 and 2736.

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8