Find the magnitude of the vector that begins at (1,1) and ends at (-8,12). a. 15.81
b. 14.76
c. 14.21
d.04

The correct answer is C (14.21)

Explanation:

(We can use the Distance Formula to find a vector’s magnitude)

Let (x1, y1) be (1, 1) and (x2, y2) be (-8, 12)

Distance
= sqrt((x2 - x1)^2 + (y2 - y1)^2)
= sqrt((- 8 - 1)^2 + (12 - 1)^2)
= sqrt((-9)^2 + 11^2)
= sqrt(81 + 121)
= sqrt(202)
≈ 14.21